mcjohnjohn

65536 subnets and 254 hosts for each subnet

mcjohnjohn

how did 65536  being calculated? mind giving me an idea if it's too much to write?
et1984 發表於 2012-2-15 15:12

example class A: 10.x.x.x
example class C: 10.0.0.x
as a result, 1 class A = 256*256 = 65536 class C
for each subnet, the first and last IP addresses are reserved, so each subnet can have 256-2 = 254 hosts

sorry for my laziless in previous post.

mcjohnjohn

I think I get it....so if it's a class A 10.0.0.0 with a class b mask then it'll be reversed 254*254 ...
et1984 發表於 2012-2-15 17:50

if class A -> class B, it should be:
1. 256 subnet
2. 256*256 - 2 hosts =  65534 (Not 254*254)

mcjohnjohn

ah ! right! thanks thanks....sigh just a simple mistake will ruin the whole network....
et1984 發表於 2012-2-16 14:37

don't mention it la, we are LYK ar ma.

mcjohnjohn

just wonna confirm I didn't get it wrong again  so let's say my first question
class A ---> class  ...
et1984 發表於 2012-2-16 16:34

Great job! I always say that LYK members are all talent and genius, and you are definitely one of them!

mcjohnjohn

How many subnets can you make if you want to break up the 200.1.200.0 network into pieces that conta ...
et1984 發表於 2012-2-17 06:42

just need 5 octets for 30 hosts.
2^5 =32, remove the first and last IP address, there are 30 IP addresses
if 200.1.200.0 is a class C network, it can have 2^3 = 8 subnets for 30 hosts

mcjohnjohn

Hehe....I guess the instructor is asking for real life situation because it is right for 5 bits f ...
et1984 發表於 2012-2-17 15:14

real life situation rocks! hahaha